10x^2-81x+8=0

Solution for 10x^2-81x+8=0 equation:

10x^2-81x+8=0

a = 10; b = -81; c = +8;
Δ = b2-4ac
Δ = -812-4·10·8
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-79}{2*10}=\frac{2}{20}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+79}{2*10}=\frac{160}{20}
=8
$